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Voltage Divider Calculator

Output voltage, current and power for a two-resistor divider.

Reviewed by the Calculation Machine team · Updated 24 October 2026 · How we check our maths

Your values

ⓘ Live results

Results
Output voltage
3.8367 V
Current through the divider
0.8163 mA
Power in R1
6.664 mW
Power in R2
3.132 mW
Total power
9.796 mW
Divider output impedance
3197.3 Ω

Quick answer

A voltage divider's output is Vout = Vin × R2 ÷ (R1 + R2), where R1 is the top resistor and R2 the bottom one. The supply splits in proportion to the resistances, so 12 V across 10 kΩ over 4.7 kΩ gives 12 × 4,700 ÷ 14,700 = 3.84 V. Anything connected to the output sits in parallel with R2 and lowers Vout.

What the Voltage Divider calculator does

This calculator gives the unloaded output voltage of a two-resistor divider, the current flowing through the chain, the power dissipated in each resistor and the divider's output (Thevenin) impedance. Enter an optional load resistance and it also shows the loaded output voltage and how far it drops.

Dividers are used to scale a battery or sensor voltage down into a microcontroller's ADC range, to set feedback voltages on regulators, and to bias transistor inputs. They are a poor choice for powering anything that draws real current, because the output sags as soon as current is taken from it. For that, use a regulator.

The maths is Ohm's law applied to resistors in series. To pick standard part values, check them with the resistor color code calculator or combine two parts using the series/parallel calculator. Real resistors carry tolerances of 1% or 5%, so the actual output can differ by roughly that much.

The formula

Vout = Vin × R2 ÷ (R1 + R2) I = Vin ÷ (R1 + R2) Rout = R1 × R2 ÷ (R1 + R2) Loaded: R2′ = R2 × RL ÷ (R2 + RL), then Vout = Vin × R2′ ÷ (R1 + R2′)

Formula variables
SymbolMeaningUnit
VinSupply voltage across the whole dividerV
R1Top resistor, between Vin and the outputΩ
R2Bottom resistor, between the output and groundΩ
RLLoad connected from the output to ground (optional)Ω
ICurrent through the divider with no loadA (shown in mA)
RoutOutput impedance: R1 and R2 in parallelΩ

This is the standard series-resistor result found in any circuit-analysis textbook, derived from Ohm's law and Kirchhoff's voltage law. It assumes ideal DC conditions. With AC signals, capacitance at the output (including an ADC's sampling capacitor) forms a low-pass filter with Rout, and for capacitive or inductive dividers you need impedances rather than resistances.

Worked examples

12 V down to about 3.8 V

A 12 V rail scaled down with a 10 kΩ top resistor and 4.7 kΩ bottom resistor, nothing connected yet.

Inputs

  • Input voltage12 V
  • R1 (top)10000 Ω
  • R2 (bottom)4700 Ω
  • Load resistance (optional) Ω

Result

  • Output voltage3.8367 V
  • Current through the divider0.8163 mA
  • Power in R16.664 mW
  • Power in R23.132 mW
  • Total power9.796 mW
  • Divider output impedance3197.3 Ω

The divider draws under 1 mA and wastes under 10 mW, which is fine for a mains-powered device. The 3.2 kΩ output impedance is low enough for most microcontroller ADC inputs.

5 V to 3.3 V, then loaded

A 10 kΩ / 20 kΩ divider meant to give 3.3 V, connected to an input that looks like a 20 kΩ resistance to ground.

Inputs

  • Input voltage5 V
  • R1 (top)10000 Ω
  • R2 (bottom)20000 Ω
  • Load resistance (optional)20000 Ω

Result

  • Output voltage3.3333 V
  • Current through the divider0.1667 mA
  • Power in R10.278 mW
  • Power in R20.556 mW
  • Total power0.833 mW
  • Divider output impedance6666.7 Ω

Unloaded it gives 3.33 V, but the 20 kΩ load halves the effective bottom resistance and the output collapses to 2.5 V. A load ten times R2 or more, or an op-amp buffer, avoids this.

Measuring a 24 V supply with an ADC

A battery-monitor divider of 100 kΩ over 10 kΩ feeding a 3.3 V ADC.

Inputs

  • Input voltage24 V
  • R1 (top)100000 Ω
  • R2 (bottom)10000 Ω
  • Load resistance (optional) Ω

Result

  • Output voltage2.1818 V
  • Current through the divider0.2182 mA
  • Power in R14.76 mW
  • Power in R20.476 mW
  • Total power5.236 mW
  • Divider output impedance9090.9 Ω

The 11:1 ratio puts 24 V at about 2.18 V, leaving headroom for a charging battery at higher voltage. Multiply the ADC reading by 11 in firmware to recover the supply voltage.

Choosing resistor values: current versus loading

The ratio R2 ÷ (R1 + R2) sets the output voltage; the absolute size of the resistors sets everything else.

  • Lower values (100 Ω – 10 kΩ): stiffer output that barely moves under load, but more current drawn and more heat. Avoid on battery devices that must sleep for months.
  • Medium values (10 kΩ – 100 kΩ): the usual choice for feeding an ADC or logic input. Many microcontroller datasheets recommend a source impedance of about 10 kΩ or less for full ADC accuracy.
  • High values (above 1 MΩ): almost no current, but leakage, noise pickup and input bias currents start to shift the reading. Add a small capacitor (for example 100 nF) from output to ground to steady an ADC reading if the signal changes slowly.

As a rule of thumb, keep the load at least 10 times R2 for less than about 10% error, and at least 100 times for around 1%.

Common target ratios with standard E12/E24 values

These pairs use widely stocked resistor values. Results are unloaded and ignore tolerance.

Practical divider pairs
GoalR1R2Output
5 V → 3.3 V logic10 kΩ20 kΩ3.33 V
5 V → 3.3 V logic1 kΩ2 kΩ3.33 V
12 V → about 3.8 V10 kΩ4.7 kΩ3.84 V
Halve any voltage10 kΩ10 kΩVin ÷ 2
24 V → about 2.2 V100 kΩ10 kΩ2.18 V

Mistakes that make a divider read wrong

  • Powering a load from it: an LED, relay or motor needs current; the output will collapse. Use a regulator, or for an LED a series resistor sized with the LED resistor calculator.
  • Swapping R1 and R2: R2 is always the resistor to ground. Swapping them gives Vin × R1 ÷ (R1 + R2) instead.
  • Sizing for the nominal voltage: size the divider for the highest voltage the source can reach (a "12 V" lead-acid battery can exceed 14 V on charge), not its nominal voltage.
  • Forgetting resistor power ratings: at high input voltages, check the mW figures against the resistor's rating (commonly 125 mW or 250 mW for small through-hole and SMD parts) and the resistor's maximum working voltage.

How to use the Voltage Divider Calculator

  1. 1Enter the supply voltage across the whole divider in volts.
  2. 2Enter R1, the top resistor between the supply and the output, in ohms (10 kΩ = 10000).
  3. 3Enter R2, the bottom resistor between the output and ground, in ohms.
  4. 4Optionally enter the input resistance of whatever the output feeds (from its datasheet) to see the loaded voltage.
  5. 5Check the current and power figures against your power budget and the resistors' ratings.

Frequently asked questions

Why is my voltage divider output lower than calculated?

Something connected to the output is drawing current, which acts like a resistor in parallel with R2. Enter that load in the calculator; if the drop is too large, use smaller resistors or add an op-amp buffer.

Can I use a voltage divider to power a device?

Not reliably. The output voltage changes with the load current, and the divider wastes power continuously. A linear or switching regulator holds the voltage steady.

How do I get 3.3 V from 5 V with resistors?

Use a 1:2 ratio such as 10 kΩ on top and 20 kΩ on the bottom, which gives 3.33 V. This suits one-way logic signals into a 3.3 V input, not supplying power.

How do I work out R2 for a target voltage?

Rearrange the formula: R2 = R1 × Vout ÷ (Vin − Vout). For 12 V to 3 V with R1 = 10 kΩ, R2 = 10,000 × 3 ÷ 9 = 3.33 kΩ, so 3.3 kΩ is the nearest standard value.

What is the output impedance of a voltage divider?

It equals R1 and R2 in parallel, R1 × R2 ÷ (R1 + R2). This is the source resistance an ADC or amplifier sees when it reads the divider.

References

  • The Art of Electronics (3rd edition), Horowitz and Hill — Cambridge University Press
  • Fundamentals of Electric Circuits, Alexander and Sadiku — McGraw-Hill

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